If it's not what You are looking for type in the equation solver your own equation and let us solve it.
4x^2+61x-98=0
a = 4; b = 61; c = -98;
Δ = b2-4ac
Δ = 612-4·4·(-98)
Δ = 5289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(61)-\sqrt{5289}}{2*4}=\frac{-61-\sqrt{5289}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(61)+\sqrt{5289}}{2*4}=\frac{-61+\sqrt{5289}}{8} $
| -6(-8x+6)+8(-4+x)=-12 | | 2x-23=43 | | 3x+(-2)=(-29) | | 180=x+(0.5x+3) | | 4^-x=4.2 | | 2.4x+5–7.4x=15 | | 4^-x=4. | | -5(a-3)=-55 | | -10=5(x+3)+3(x+5) | | 0.20x+3=9-0.60 | | 5(3u-4)=6 | | x+97+43=180 | | 3x+(-2)=29 | | (9b/5)=b+8 | | -12-2n-5=-2n-14 | | -8=+b/6 | | -2(m-5)=12 | | 5/4b+7=7/8b+9 | | 180=x+(1/2x+3) | | 10-15/7+x=57/7+x | | 2(x+7)=3(2x+3)-1 | | |x+4|=-1/9 | | 8-9t=9t-15 | | -8+8b=6b-14 | | d/2+2=-3 | | 100x^2+3=28 | | 4g=200 | | 6=9y-3y | | 2+3n=9+4n | | 2(x+1)-3x=15 | | 5x-19+6x+12=180 | | 5=2(2m-8)=25 |